Question

please solve this equation

t²-t-20=0​

Answer 1

Answer:

t= 20 or 22

Step-by-step explanation:

t^2 - 2t - 20 = 0

t^2-2t= 20

t(t-2)= 20,t-2=20

t=20+2

t=22

Answer 2

Answer:

First of all, make sure you use the same variable throughout. “T” is not the same as “t”.

Second, familiarize yourself with the quadratic formula, and use it most anytime that you cannot factor the quadratic expression. For any equation of form at^2 + bt + c = 0, the solution for t will be

t = (-b +/- sqrt (b^2 - 4ac)) / 2a (the quadratic formula)

In the example you’ve given, a = 1, b = -1, and c = -4. Therefore,

t = (-(-1) +/- sqrt ((-1)^2 - 4 * 1 * -4)) / (2 * 1)

t = (1 +/- sqrt (1 + 16)) / 2 = { ((1 + sqrt (17)) / 2, ((1 - sqrt (17)) / 2 }