Question

please solve this equation (very urgently) ​

Answer 1

Answer:

(I) 0.6 ampere from 10 ohm resistor and 0.4 ampere from 15 ohm resistor

(ii) potential difference in PQ is 5 volt and PR is 6 volt

(iii) equivalent resistance is 11 oh

Explanation

(III)

resistance between Q and R are connected in parallel

equivalent resistance = R1* R2/R1 + R2 = 10*15/10+15 = 150/25 = 6 ohm

resistance between P and R are connected in series= R1 + R2 = 5 ohm + 6 ohm = 11 ohm

(ii)

between P and Q

Potential difference = current*resistance = 1 ampere*5ohm = 5 volt

between Q and R

potential difference = current* resistance = 1 ampere*6ohm = 6 volt

(I)

in 10 ohm resistance

current = potential difference/resistance = 6 volt / 10 ohm = 0.6 ampere

in 15 ohm resistance

current = potential difference/resistance = 6 volt / 15 ohm = 0.4 ampere