Question

Please solve this. Exam at 10:00 am today not able to solve.

1st one only not the second one.

Answer 1

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Question:-



Solution:-


tan(A-B)=1/√3

tan(A+B)=√3

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Note:-

tan 30°=1/√3

tan 60°=√3

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tan(A-B)=1/√3

tan(A+B)=√3

tan(A-B)=tan 30°
tan(A+B)= tan 60°


A-B=30°. {Equation 1}
A+B=60°. {Equation 2}

Solving by Elimination method;

A-B=30°
A+B=60°

_________
-2B=-30

B=30/2=15°

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Substitute the value of B in Equation 1

A-B=30°

A-15°=30°

A=30°+15°

A=45°


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Thanks!!!!