Question

*please solve this exercise 4.3 question no 1 of class 7th ncert ..i will mark you Brainlist urgent plz solve...okkk thank!! you​*​ please solve in copy

Answer 1

Step-by-step explanation:

a. 2y+5/2=37/2

2y= 37/2-5/2

2y= 18.5-2.5 /2

2y= 16/2

y= 16/2×2

y =16/4= 4

b. 5t=28=10

5t=10 -28

5t= -18

t= -18/5=3.6

c.a/5+3 =2

a/5= 2-3

a/5= -1

a= 5×(-1)

a= -5

d.q/4+7=5

q/4 = 5-7

q/4 = 2

q= 4×2 = 8

e.5 /2 x=10

5x= 10×2

5x= 20

x= 20/5= 100

f.5/2x= 25/4

x=25/4-5/2

x= 6.25-2.5/4

x= 3.75/4

h.6z +10=-2

6z= -2-10

6z= 12

z= 12/6= 2

i. 3l/2=2/3

3l×3=2×2(by cross multiplication?)

3l×3= 4

3l= 3/4

3l= 0.75

l= 0.75/3

l= 0.25

j. 2b/3 ×5 = 3

2b /3 = 3/5 ( by cross multiplication)

2b×5=3×3

2b×5=9

2b=9/5

2b=0.8

b= 0.8/2 = 0.4

Answer 2

Answer:

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Step-by-step explanation:

check the attachment above

hope it helps

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