Question

please solve this fast​

Answer 1

Answer:

Step-by-step explanation:

taking lhs of equation

by lcm we get 2sintheta/cos^2(theta)-sin^2(theta)

=2sin theta /cos2 theta

=2sin theta/2cos^2-1

=2sin theta/1-2sin^2(theta)

Answer 2

Answer:

1/ sinx+ cosx + 1/sinx-cosx =>

(sinx-cosx)+(sinx+cosx)/(sinx-cosx)(sinx+cosx) =>

$\frac{1}{ \sin(x) + \cos(x) } + \frac{1}{ \sin(x) - \cos(x) } = \frac{2 \sin(x) }{( { \sin(x) }^{2} - { \cos(x) }^{2}) }$

(sinx^2 = 1- cosx^2 )

=>

$\frac{2sinx}{1 - 2 { \cos(x) }^{2} }$

Hence proved. Hope it helps you.