Question

Please solve this fast

Answer 1

Answer:

$\large{\boxed{\sf p=4}}$

Step-by-step explanation:

Given that x = p+1

So,

$\sf\frac{2x}{p}-\frac{x-2}{p+1}=1$

$\sf\frac{2p+1}{p}-\frac{p-1}{p+1}=1$

$\sf\frac{3}{1}-\frac{p-1}{p+1}=1$

$\sf\frac{(p+1)3-p-1}{p+1}=1$

$\sf6-p-1=1$

$\sf -p+5=1$

$\sf -p=1-5$

$\sf p=4$