Question

please solve this fast . ​

Answer 1

Explanation:

$\sf {m}_{1} = 5 \:kg \:\:\:\:\:\:\: {v}_{1} = 1\:m/s \\ \sf {m}_{2} = 2.5\:kg\:\:\:\:\:\:\: {v}_{2} = - v\:m/s \\ \\ \sf Initial \:momentum = {m}_{1}{v}_{1} + {m}_{2}{v}_{2} \\ \\ \sf Final \:momentum = 0 \\ \\ \sf By\: conservation\:of\ momentum \\ \\ \sf Initial \:momentum = final\:momentum \\ \\ \sf \longrightarrow {m}_{1}{v}_{1} +{m}_{2}{v}_{2} = 0 \\ \\ \sf \longrightarrow 5 × 1 + 2.5 × ( - v) = 0 \\ \\ \sf \longrightarrow 5 = 2.5v \\ \\ \sf \longrightarrow 2.5v = 5 \\ \\ \sf \longrightarrow v = \frac{5}{2.5} \\ \\ \sf \longrightarrow v = 2 \: m/s$

❣️NIRANJAN45❣️

Answer 2

Answer:

$\begin{lgathered}\sf {m}_{1} = 5 \:kg \:\:\:\:\:\:\: {v}_{1} = 1\:m/s \\ \sf {m}_{2} = 2.5\:kg\:\:\:\:\:\:\: {v}_{2} = - v\:m/s \\ \\ \sf Initial \:momentum = {m}_{1}{v}_{1} + {m}_{2}{v}_{2} \\ \\ \sf Final \:momentum = 0 \\ \\ \sf By\: conservation\:of\ momentum \\ \\ \sf Initial \:momentum = final\:momentum \\ \\ \sf \longrightarrow {m}_{1}{v}_{1} +{m}_{2}{v}_{2} = 0 \\ \\ \sf \longrightarrow 5 × 1 + 2.5 × ( - v) = 0 \\ \\ \sf \longrightarrow 5 = 2.5v \\ \\ \sf \longrightarrow 2.5v = 5 \\ \\ \sf \longrightarrow v = \frac{5}{2.5} \\ \\ \sf \longrightarrow v = 2 \: m/s\end{lgathered}$$