Question

please solve this fast

Answer 1

const:draw AP and DQ perpendicular to BC

Proof:In Triangle AOP and DOQ, Angle AOP=DOQ (VOP) ANGLE APO=DQO=90(BY CONST.)

By AA similarity,AOP similar to DOQ =>AP/DQ=AO/DO ------>(1) ar(ABC)=1/2(BC*AP)

and ar(DBC)=1/2(BC*DQ) ar(ABC)/ar(DBC)=AP/DQ FROM (1),

ar(ABC)/ar(DBC)=AO/DO Hence Proved

Answer 2

Hii there....
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