Question

please solve this fast.

Answer 1

let the number be x
its reciprocal=1/x
so,
its sum of its square and its resiprocal square will be:
${x}^{2} + ( { 1 \div x) }^{2}$
sum of number and its reciprocal will be
x+(1/x) .
its sq. sum is greater by 7/4 from its no. and reciprocal sum.
make it identity of (a+b) sq. by adding 2 on both side and then take all terms on r.h.s to left side and by taking their l.c.m factorise them.

Your answer will be 2.

Verify:

${2}^{2} + ( {1 \div 2)}^{2} \\ 4 + (1 \div 4) \\ 17 \div 4 \\ \\ \\ 2 + (1 \div 2) \\ 5 \div 2 \\ \\ \\ \\ \\ (17 \div 4) - (5 \div 2) \\ (17 \div 4) - (10 \div 4)...lcm \\ 7 \div 4 \\ \\ it \: is \: greater \: by \: 7 \div 4$

Answer 2

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