Math, asked by abihkrishna003, 1 year ago

please solve this fast

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Answered by khush7725
1
take R.H.S
I have consider thetha as x
cotx-tanx
cosx/sinx-sinx/cosx
take LCM
cos^2x-sin^2x/sinxcosx
as we know that sin^2x =1-cos^2x
cos^2x-(1cos^2x)/sinxcosx
cos^2x-1+cos^2x/sinxcosx
2cos^2x-1/sinxcosx
LHS=RHS
hence proved
Answered by anamika100403
1
here is ur answer.
I hv solved both RHS as well as LHS
......hope it helps
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