CBSE BOARD XII, asked by jatin4814, 1 year ago

Please solve this fast...

Compute the volume occupied by 11.2 g of the gas at NTP.
Given that the vapour density of a gas is 11.2.?

Answers

Answered by brainlystargirl
5
Heya _____

Solution is given here ____

Given ,, molecular mass of gas
= 2 X vapour density...
2 X 11.2
22.4 ......

No of Moles of gas ....

11.2 / 22.4
= 0.5

Volume of molecule of gas ....

Moles X 22.4

0.5 X 22.4

11.21 litres ... Ans ____

Thank you
Answered by Anonymous
2

Answer:

Molecular mass=2*vapour density

=2*11.2

=22.4 g

At NTP,

volume occupied by 22.4 g of gas= 22.4 l

volume of 11.2g gas = 22.4/22.4*11.2

= 11.2 l

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