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Compute the volume occupied by 11.2 g of the gas at NTP.
Given that the vapour density of a gas is 11.2.?
Answers
Answered by
5
Heya _____
Solution is given here ____
Given ,, molecular mass of gas
= 2 X vapour density...
2 X 11.2
22.4 ......
No of Moles of gas ....
11.2 / 22.4
= 0.5
Volume of molecule of gas ....
Moles X 22.4
0.5 X 22.4
11.21 litres ... Ans ____
Thank you
Solution is given here ____
Given ,, molecular mass of gas
= 2 X vapour density...
2 X 11.2
22.4 ......
No of Moles of gas ....
11.2 / 22.4
= 0.5
Volume of molecule of gas ....
Moles X 22.4
0.5 X 22.4
11.21 litres ... Ans ____
Thank you
Answered by
2
Answer:
Molecular mass=2*vapour density
=2*11.2
=22.4 g
At NTP,
volume occupied by 22.4 g of gas= 22.4 l
volume of 11.2g gas = 22.4/22.4*11.2
= 11.2 l
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