Question

please solve this fast first answer will be marked brainliest
$\sqrt[3]{3} + 2 \sqrt{27} + \frac{1}{ \sqrt{3} }$
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Answer 1

Answer:

$\sqrt[3]{3} + 2 \sqrt{27} + \frac{1}{ \sqrt{3} } \\ \frac{ \sqrt[3]{3} \times \sqrt{3} + 2 \sqrt{9 \times 3 \times 3 } + 1 }{ \sqrt{3} } \\ \frac{ \sqrt[3]{3} \times \sqrt{3} + 2 \times 9 + 1 }{ \sqrt{3} }$