Question

Please solve this fast !! (Inappropriate answers will be reported)
I will mark you BRAINLIEST if elaborate and correct

Answer 1

Explanation:

4a

2

+12ab+9b

2

−25c

2

= \frac{[(2a)^{2}+2\times 2a \times 3b+(3b)^{2}]-(5c)^{2}}{2a+3b+5c}=

2a+3b+5c

[(2a)

2

+2×2a×3b+(3b)

2

]−(5c)

2

= \frac{(2a+3b)^{2} - (5c)^{2}}{(2a+3b+5c) }=

(2a+3b+5c)

(2a+3b)

2

−(5c)

2

\blue{ ( By \: Algebraic \:Identity )}(ByAlgebraicIdentity)

\boxed { \pink { x^{2} + 2xy + y^{2} = (x+y)^{2} }}

x

2

+2xy+y

2

=(x+y)

2

= \frac{ [(2a+3b) + 5c][(2a+3b)-5c]}{(2a+3b+5c)}=

(2a+3b+5c)

[(2a+3b)+5c][(2a+3b)−5c]

\blue{ ( By \: Algebraic \:Identity )}(ByAlgebraicIdentity)

\boxed { \pink { x^{2} - y^{2}= (x+y)(x-y) }}

x

2

−y

2

=(x+y)(x−y)

= \frac{ (2a+3b + 5c)(2a+3b -5c)}{(2a+3b+5c)}=

(2a+3b+5c)

(2a+3b+5c)(2a+3b−5c)

/* After cancellation ,we get */

= (2a+3b-5c)=(2a+3b−5c)

Therefore.,

\red {\frac{4a^{2}+12ab+9b^{2}-25c^{2}}{2a+3b+5c}} \green {= (2a+3b-5c)}

2a+3b+5c

4a

2

+12ab+9b

2

−25c

2

=(2a+3b−5c)

•••♪