Question

please solve this fast its urgent

Answer 1

Answer:

Please mark it as brainliest :-D

Answer 2

Answer:

Step-by-step explanation:

$2x^2+\frac{5}{3}-2=0\\\\ 3(2x^2+\frac{5}{3}-2)=0\\\\6x^2+9x-4x-6=0\\\\3x(2x+3)-2(2x+3)=0\\\\(3x-2)(2x+3)=0\\\\3x-2=0\\ or\\ 2x+3=0\\x=\frac{2}{3} \\or\\x=\frac{-3}{2}$