Question

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Answer 1

Answer:

Given,

sin θ + cosec θ = 2

sin θ + (1/sin θ) – 2 = 0

sin2θ + 1 – 2 sin θ = 0

(sin θ – 1)2 = 0

sin θ – 1 = 0

sin θ = 1

cosec θ = 1/sin θ = 1

sin10θ + cosec10θ = (1)10 + (1)10 = 1 + 1 = 2

Step-by-step explanation:

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