please solve this fast .very urgent whoever gives the correct first will be marked as brainliest and I will follow them.
question: show that.......... Refer the above pic
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Answered by
1
Answer:
x-2=0
×=2
Step-by-step explanation:
p(x) = x³- 6x²+ 11x - 6
p(2)=(2)³-6(2)³+11(2)-6
= 8-48+22-6
= 8-26-6
=8-32
= -24
since -24 is not equal to 0
therefore x-2 is not a factor of p(x)=x³-6x²+11x-6
I hope i'm able to help you by this
Answered by
3
GIVEN :-
- DIVISOR : x - 2
- p (x) = x³ - 6x² + 11x - 6
TO FIND :-
- that ( x - 2 ) is a factor of x³ - 6x² + 11x - 6
SOLUTION :-
NOW WE HAVE TO PROVE THAT ( x - 2 ) is a factor of x³ - 6x² + 11x - 6
so if values of x of divisor brings result 0 after putting in p(x) : x³ - 6x² + 11x - 6 so it will be a factor
x - 2 = 0
x = 2
now put the value of x in dividend
OTHER INFORMATION :-
NOTES FOR POLYNOMIAL
- A term is either a variable or a single number or it can be a combination of variable and numbers.
- The degree of the polynomial is the highest power of the variable in a polynomial.
- A polynomial of degree 1 is called as a linear polynomial.
- A polynomial of degree 2 is called a quadratic polynomial.
- A polynomial of degree 3 is called a cubic polynomial.
- A polynomial of 1 term is called a monomial.
- A polynomial of 2 terms is called binomial.
- A polynomial of 3 terms is called a trinomial.
- A real number ‘a’ is a zero of a polynomial p(x) if p(a) = 0, where a is also known as root of the equation p(x) = 0.
- A linear polynomial in one variable has a unique zero, a polynomial of a non-zero constant has no zero, and each real number is a zero of the zero polynomial.
Remainder Theorem:
- If p(x) is any polynomial having degree greater than or equal to 1 and if it is divided by the linear polynomial x – a, then the remainder is p(a).
Factor Theorem :
- x – c is a factor of the polynomial p(x), if p(c) = 0. Also, if x – c is a factor of p(x), then p(c) = 0.
- The degree of the zero polynomial is not defined.
other identities :
- (x + y + z)² = x² + y² + z²+ 2xy + 2yz + 2zx
- (x + y)³ = x³ + y³ + 3xy(x + y)
- (x – y)³ = x³– y³– 3xy(x – y)
- x³ + y³+ z³ – 3xyz = (x + y + z) (x² + y² + z²– xy – yz – zx)
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