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Let a and d be the first term and common difference of A.P.
nth term of A.P., an = a + (n – 1) d
∴ a3 = a + (3 – 1) d = a + 2d
a7 = a + (7 – 1) d = a + 6d
Given, a3 + a7 = 6
∴ (a + 2d) + (a + 6d) = 6
⇒ 2a + 8d = 6
⇒ a + 4d = 3 ...(1)
Given, a3 × a7 = 8
nth term of A.P., an = a + (n – 1) d
∴ a3 = a + (3 – 1) d = a + 2d
a7 = a + (7 – 1) d = a + 6d
Given, a3 + a7 = 6
∴ (a + 2d) + (a + 6d) = 6
⇒ 2a + 8d = 6
⇒ a + 4d = 3 ...(1)
Given, a3 × a7 = 8
vaishu334:
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the answer is third term + seventh term is equal to 6 let a be the first term and DB the common difference that is a + 2 b + A + 60 is equal to 6 next to A + 8 d is equal to 6 simplify that a + 4 is equal to 3 next it is tell that if the product of the 7th and 3rd term is 8 so that( a + 2D
balance( A + 2d)(A+6d)=8
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