please solve this.....fasttt
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4
Step-by-step explanation:
We use a topic called cyclicity here. It basically helps us find the last digits of exponents.
For eg.
2¹ = 2
2² = 4
2³ = 8
2⁴ = 16
2⁵ = 32
Here, we can see the units digit of the powers of 2 start repeating after every 4 powers, so we say that 2 has a cyclicity of 4.
For this, we only need the last digit of the given number.
2003²⁰⁰⁶ + 2004²⁰⁰⁶ + 2007²⁰⁰⁶ will have the same unit's digit as
3²⁰⁰⁶ + 4²⁰⁰⁶ + 7²⁰⁰⁶
Cyclicity of 3 = 4
Cyclicity of 4 = 2
Cyclicity of 7 = 4
2006 ÷ 4 leaves a remainder 2
2006 ÷ 2 leaves a remainder 0(Here we take 2 for ease of calculation)
3² + 4² + 7²
= 9 + 16 + 49
=Last digit 4
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