Please solve this.......Find a³+ b³
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HEYA !!!!! YOUR ANSWER IS HERE......
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HOPE IT HELPS YOU, DEAR......
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HOPE IT HELPS YOU, DEAR......
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Heena66:
is your answer correct
sorry .....Palak....Your answer is correct but I can not understand anything
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Hey there!!
Given : a/b + b/a = 1 -----------------(1)
=> take LCM of denominator
We get,.
=> (a²+ b²) /ab = 1
=> a² + b² = ab ----------------(2)
Now we have to find :
=> a³ + b³ = (a+b) (a²+b² -ab) -----------(3)
Put the value of (a² + b²) in eqn (3) we get,
=> a³ + b³ = ( a+b) (ab - ab) = (a+b) ×0 = 0
So we have, (a³+b³) = 0 ans...
_______________________________________
Hope it"ll help u
Given : a/b + b/a = 1 -----------------(1)
=> take LCM of denominator
We get,.
=> (a²+ b²) /ab = 1
=> a² + b² = ab ----------------(2)
Now we have to find :
=> a³ + b³ = (a+b) (a²+b² -ab) -----------(3)
Put the value of (a² + b²) in eqn (3) we get,
=> a³ + b³ = ( a+b) (ab - ab) = (a+b) ×0 = 0
So we have, (a³+b³) = 0 ans...
_______________________________________
Hope it"ll help u
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