Question

please solve this

Find the H.C.F of 81 and 237 .............​

Answer 1

Answer:

237 = 81 × 2 + 75

81 = 75 × 1 + 6

75 = 6 × 12 + 3

6 = 3 × 2 + 0

3 = 75 – 6 × 12

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Answer 2

$\bf{\underline{\underline{QUESTION:-}}}$

• Find the H.C.F of 81 and 237

$\bf{\underline{\underline{SOLUTION:-}}}$

• Clearly 81 < 23

So,

• a = 81
• b = 237

Then,

81 ) 237 ( 2

⠀⠀ -162

⠀⠀ ⠀75

Therefore ,

• By division lemma.
• => 237 = 81 × 2 + 75

Now,

• Consider the divisor 81 and remainder 75 we have ,

75 ) 81 ( 1

⠀⠀ -75

⠀⠀ 6

• => 81 = 75 × 1 + 6

Further,

6 ) 75 ( 12

⠀ -72

⠀ 3

• => 75 = 6 × 12 + 3

Also

3 ) 6 ( 2

⠀⠀-6

⠀⠀ 0

• => 6 = 3 × 2 + 0
• At this stage remainder is 0

$\bf{\underline{\underline{HENCE:-}}}$

• the H.C.F is 3