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Given Equation is 4x^2 - 9y^2 - 2x - 3y.
It can be written as
= > 4x^2 + 6xy - 6xy - 9y^2 - 2x - 3y
= > 2x(2x + 3y) - 3y(2x + 3y) - 1(2x + 3y)
= > (2x - 3y - 1)(2x + 3y).
Therefore, factorization of 4x^2 - 9y^2 - 2x - 3y = (2x - 3y - 1)(2x + 3y).
Hope this helps!
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