Question

Please solve this for me

Answer 1

area of a quadrilateral = area of ∆ABC + area of ∆PQD

=> [(6×8)]+[(10×8)] sq cm

=> [48+80] sq cm

=> 128 sq cm

$area \: of \: angle \: abc \: + \: area \: of \: angle \: pqd = \: 6 \times 8 + 10 \times 8 = 48 + 80 = 128$

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Answer 2

Step-by-step explanation:

area of a quadrilateral = area of ∆ABC + area of ∆PQD

=> [(6×8)]+[(10×8)] sq cm

=> [48+80] sq cm

=> 128 sq cm

area of angle abc + area of angle pqd = 6 times 8 + 10 times 8 = 48 + 80 = 128 area of angle abc+area of angle pqd=6×8+10×8=48+80=128

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