Math, asked by brilliantworld, 2 months ago

please solve this for me please math . ​

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Answers

Answered by Anonymous
40

Given :

  • We have to find the Area of the Rectangle whose Sides are 6m and 20cm

To find :

  • The area of the Rectangle

Solution :

★ Concept :

We have to find the Area of the Rectangle but we can clearly see that the sides are not equal because 6 is in metre and 20 is in Centimetre So, before finding the Area we have to first make both the units So, let's do it!

{\underline{\underline{\green{\mathfrak{As \ we \ know \ that}}}}}

\;\boxed{\sf{\pink{Area_{\:(rectangle)} = Length \times Breadth}}}

\;\boxed{\sf{\purple{1_{\:(m)} = 100{\:(cm)}}}}

: \implies \sf{6 \ m} \times \sf{100 \ cm}

: \implies  {\underline{\boxed{\pink{\mathfrak{600 \ m}}}}}

Now, we can find the Area as both the units are equal

: \implies \sf{600 \ cm \ \times 20 \ cm}

: \implies {\underline{\boxed{\pink{\mathfrak{12,000 \ cm^{2}}}}}}

•°• Hence, verified! that the Area is \sf{12,000 \ cm^{2}}

Diagram :

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 20 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 6 m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀⠀⠀⠀

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Answered by Anonymous
32

Answer:

\bf\red{Question}

  • Find the area of rectangle whose sides are 6 m and 20 cm.

\bf\red{Conversion}

We have to convert m \red\leadsto cm

1 m = 100 cm

6 m = 6 × 100 = 600 cm

\bf\red{Given}

Length \red\leadsto 600 cm [ 6m ]

Breadth \red\leadsto 20 cm

\bf\red{To\:find}

  • We have to find the area of rectangle

\bf\red{Formula}

Area of rectangle = Length × Breadth

\bf\red{Solution}

Length \red\leadsto 600 cm [ 6m ]

Breadth \red\leadsto 20 cm

Area of rectangle = Length × Breadth

ATQ,

= 600 × 20

= 12000

Hence Proved! 12000 cm² is the area of rectangle.

__________________________________

\bf\red{Diagram:-}

\begin{gathered}\begin{gathered} \green{\tt6 \: m\:[600\: cm]} \: \: \: \: \: \: \: \: \: \: \: \\ \orange{\boxed{\begin{array}{}\bf { \blue{}}\\{\qquad \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:}{}\\ { \sf{ }}\\ { \sf{ }} \\ \\ { \sf{ }}\end{array}}} \green{ \tt \:20 \: cm} \end{gathered}\end{gathered}

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