Please solve this for x and y.
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Answer 1: If equations has infinitely many solutions then
a1/a2=b1/b2=c1/c2
c/12=3/c=(3-c)/-c
c/12=3/c
36=c^2
√36=c
6=c
Answer 2: Equations has infinitely many solutions then
a1/a2=b1/b2=c1/c2
2/k+1=3/2k-1=7/4k+1
2(2k+1)=3(k+1)
4k-2=3k+3
4k-3k=3+2
k=5
Answer 3: Equations has a unique solution then
a1/a2=b1/b2≠c1/c2
1/3=2/k≠5/-15
1/3=2/k
k=6
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