Math, asked by diyapardhi2006, 1 month ago

Please solve this for x and y.​

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Answers

Answered by saumyasingh1569
1

Answer:

Answer 1: If equations has infinitely many solutions then

a1/a2=b1/b2=c1/c2

c/12=3/c=(3-c)/-c

c/12=3/c

36=c^2

√36=c

6=c

Answer 2: Equations has infinitely many solutions then

a1/a2=b1/b2=c1/c2

2/k+1=3/2k-1=7/4k+1

2(2k+1)=3(k+1)

4k-2=3k+3

4k-3k=3+2

k=5

Answer 3: Equations has a unique solution then

a1/a2=b1/b2≠c1/c2

1/3=2/k≠5/-15

1/3=2/k

k=6

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