Question

please solve this friends...
question no. 30

Answer 1

Answer:

tanθ = 1/2 (or) 1

Step-by-step explanation:

Given Equation is sin²θ - 3sinθcosθ + 1 = 0

⇒ 1 + sin²θ = 3sinθcosθ

Divide by 'cos²θ', we get

⇒ (1/cos²θ) + (sin²θ/cosθ) = (3sinθcosθ)/(cos²θ)

⇒ sec²θ + tan²θ = 3tanθ

⇒ (1 + tan²θ) + tan²θ = 3 tanθ

⇒ 1 + 2 tan²θ = 3 tanθ

⇒ 2 tan²θ - 3 tanθ + 1 = 0

⇒ 2 tan²θ - 2 tanθ - tanθ + 1 = 0

⇒ 2 tanθ(tanθ - 1) - (tanθ - 1) = 0

⇒ (2 tanθ - 1)(tanθ - 1) = 0

⇒ tan θ = 1/2 (or) 1

Hope it helps!

Answer 2

Step-by-step explanation:

please mark me as brainliest