Question

please solve this frnds​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

       

$\huge\boxed{\ \ \ \ \ \ \ \huge\boxed{\ \ \ \ \ \ \ \huge\boxed{\ \ \ \ \ \ \ \bold{x=\pm 3}\ \ \ \ \ \ \ }\ \ \ \ \ \ \ }\ \ \ \ \ \ \ }$

$\sf{Distance between A \& B = 5} \ \\ \\ \Rightarrow\ \sqrt{(x-0)^2+(-4-0)^2}=5 \\ \\ \Rightarrow\ \sqrt{x^2+(-4)^2}=5 \\ \\ \Rightarrow\ \sqrt{x^2+16}=5 \\ \\ \Rightarrow\ x^2+16=5^2 \\ \\ \Rightarrow\ x^2+16=25 \\ \\ \Rightarrow\ x^2=25-16 \\ \\ \Rightarrow\ x^2=9 \\ \\ \Rightarrow\ x=\sqrt{9} \\ \\ \Rightarrow\ x=\bold{\pm 3}$

$\therefore\ \ \sf{The values of} \ x\ \sf{are} \ \ \bold{3\ \ \&\ -3}$

$\sf{Hope this helps. Plz mark it as the brainliest. \\ \\ Plz ask me if you've any doubt. \\ \\ \\ Thank you. :-))}$