Math, asked by harshitmaheshwari16, 11 months ago

PLEASE solve THIS GIVE ME ANSWER​

Attachments:

Answers

Answered by Gayathri10rocking
0

Step-by-step explanation:

first rationalize 2+√3/2-√3 by multiplying with 2+√3/2+√3

you'll get the answer as 4+4√3+3/4-3 {by using the identity }

the final answer will be 7+4√3

hence a=7

b=4

Answered by AdityeshRaghav
0

Answer:

A=7 & B=4

Step-by-step explanation:

So we have, 2+√3/2-√3= a+b√3 (i)

therefore....

=> Rationalising the denominator...

=> 2+3(2+3)/ 2-3(2+3)

=> In numerator we have..

=> (2+3)^2, Using (a+b)^2 = a^2+b^2+2ab

We have,

=(2)^2+2(2)(3)+(3)^2

= 4+43+3

=7+43

=> In Denominator we have...

=> 2-3(2+3)... Using (a+b)(a-b) = a^2+b^2

=> 2^2+3^2

=> 4-3=1.

=>Therefore, On solving We have..

=>7+43/1=a+b3 -(ii)

=> On observing eqn (ii)

=> We can say that...

a=7 & B=4

This Is Your Answer...

Hope It Helps You.... :)

Similar questions