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given 5th term is zero
a+4d=0
a=-4d
33rd term is 4 times the 12th term
a+32d=4(a+11d)
3a+12d=0
a+4d=0
it is valied condition
hence it is proved
a+4d=0
a=-4d
33rd term is 4 times the 12th term
a+32d=4(a+11d)
3a+12d=0
a+4d=0
it is valied condition
hence it is proved
Answered by
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Note: We know that nth term of an AP = a + (n - 1) * d.
Now,
Given that 5th term of an AP is zero.
= > a + (5 - 1) * d = 0
= > a + 4d = 0.
= > a = -4d --------- (1)
33rd term:
= > a + (33 - 1) * d
= > a + 32d
= > -4d + 32d
= > 28d ----------------------- (2)
12th term:
= > a + (12 - 1) * d
= > a + 11d
= > -4d + 11d
= > 7d ------------------------ (3)
From Equation (3) & (2), we can say that
33rd term = 4 * (12th term)
Hope this helps!
Now,
Given that 5th term of an AP is zero.
= > a + (5 - 1) * d = 0
= > a + 4d = 0.
= > a = -4d --------- (1)
33rd term:
= > a + (33 - 1) * d
= > a + 32d
= > -4d + 32d
= > 28d ----------------------- (2)
12th term:
= > a + (12 - 1) * d
= > a + 11d
= > -4d + 11d
= > 7d ------------------------ (3)
From Equation (3) & (2), we can say that
33rd term = 4 * (12th term)
Hope this helps!
siddhartharao77:
:-)
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