Question

Please solve this... Help please​

Answer 1

Answer:

a) i^121 can also be written as,

(i^120)(i)

[(-1)^60](i)=i because i^2= -1

therfore, i^121=i

b)as same as (a)

c) i^(-705)=1/i^705

=1/(i^704)(i)

=1/((-1)^352)(i)

=i^(-1)

d) [(-1)^(1/2)]^90= (-1)^45

=-1

e)same as (a)