Question

Please solve this . Help your friend ​

Answer 1

∵ OPMN and AQBN are identical rectangles

∴ MN = BN = 4cm = AQ

Now, AD = 28

AD = DQ + AQ

⇒ 28 = DQ + AQ

⇒ 28 = DQ + 4 CM

⇒ DQ = 24 cm

Also, DQ = CN

⇒ CN = 24 cm

But ON = OC

∴ ON = 12 cm

Again, OMMN and AQNB are identical

∴ ON = QN = 12cm

⇒ OM = 8 cm

Now area of Δ QDM = 1/2 ( DQ) (MQ)

∴ ar(Δ) = 1/2 (24)(12)

⇒ ar(Δ) = 96cm²

MARK AS BRAINLIEST, IF YOU GOT IT.

Answer 2

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