Question

Please solve this
I am in hurry
TAKE 25 POINTS

Answer 1

Hi ,

cubeth root of ( x + 1 ) ( y + 2 ) ( z + 3 ) = 7

do the cube of both sides of the equation.

( x + 1 ) ( y + 2 ) ( z + 3 ) = 7³----( 1 )

let us assume ,

( 6 + 1 ) ( 5 + 2 ) ( 4 + 3 ) = 7³ ---( 2 )

compare ( 1 ) and ( 2 ) , we get

x = 6 , y = 5 , z = 4

Now ,

x × y × z = 6 × 5 × 4

= 120

I hope this helps you.

: )

Answer 2

Answer:

((x+1)*(y+2)*(z+3))⅓=7

=> x = 6 , y = 5, z = 4

=> ((6+1)*(5+2)*(4+3))⅓=7

=> (7*7*7)⅓=7

=> (7³)⅓=7

=> 7=7

=> xyz = 6*5*4 = 120