Question

please solve this I need the answer.....

Answer 1

Ello There!

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We know that area of a paralellogram = base × height

Since we have a pair of base AB and height DE, lets calculate the area of ABCD first.

ar(ABCD) = AB × DE

ar(ABCD) = 25  × 10

ar(ABCD) = 250m²

Now we have found out the area of ABCD.

We can see that we see another pair of base BC (the adjacent side we need to find) and an altitude DF.

Therefore we have another equation

ar(ABCD) = base × height

ar(ABCD) = BC × DF

       250 = BC × 20

       $\frac{250}{20}$ = BC

       12.5 = BC

∴ The value of the Adjacent side is 12.5cm

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Feel free to ask doubts in the comment section!

Thanks!

Answer 2

$\huge{hey \: mate \: here \: is \: your \: answer \:}$

$\textbf{Given That...}$

One Side Of Parallelogram ABCD Is 25cm (AB) And It's Corresponding Altitude Is Equal To 10m, And it's also

Given That Another Altitude On Adjacent Side BC Is 20m . Now We Need To Find The Length or Measure Of BC .

$\textbf{Solution...}$

$\textbf{Now To Find The Length Of BC , Follow The Simple Steps....}$

1 )) Find Area Of ABCD By Given Information .....

So For This It's Given That ....

Length Of ( Base ) AB = 25m

And

Length Of Altitude DM = 10m

Now We Need To Find The Area Of Parallelogram ABCD ,

So For This We Have a Direct Formula That is ➡️

$\boxed{area \: of \: \: parallelogram \: = \: (base \: \times \: height \: (altitude) \: )}$

That is .......

$\boxed{ar (ABCD) =AB \: \times \: DM \:}$

So Now Putting Values Of Base (AB) = 25m And Altitude (DM) = 10m .. We Have ...

$ar (ABCD) = \: 25m \: \times 10m$

That is ....

$ar (ABCD) = \: 250 {m}^{2}$

So Hence The Area Of Parallelogram ABCD Is

$\boxed{250 {m}^{2}}$

$\textbf{So Now We Need To FInd Length Of (Base) BC }$

Now For BC Corresponding Altitude Is DN

That is Equal To 20m

Now By Using Same Formula Here .

We Have Area Of Parallelogram ABCD Equal To

$ar(ABCD) = \: base \: \times height$

That is ➡️

$\boxed{ar(ABCD) = BC \times DN \:}$

Now Putting Values Of Base ( BC) = BC And Altitude DN = 20m We Have ....

$ar(ABCD) = BC \times 20m$

But We Know That ar(ABCD) = 250(m)^2

So Putting This Value Here we Have ...

$BC \times 20m = 250 {m}^{2}$

Now Taking 20m To RHS We Have

$BC = \frac{250 {m}^{2} }{20m}$

That is ➡️

$\textbf{BC = 12.5m}$

$\textbf{Hence The Required Answer is }$

$\boxed{ 12.5m}$

$\huge{Be\: Brainly.....}$