please solve this. I will be thank ful to u. 100points. who is that lucky winner
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4^x + 2^(2x - 1 ) = 3^( x + 1/2 ) + 3^(x - 1/2)
By taking 3^ ( x - 1/2 ) as common from R.H.S,
(2^2)^x + 2^( 2 x - 1 ) = 3^( x - 1/2 ) ( 3 + 1 )
2^(2x ) + 2^( 2x- 1 ) = 3^( x - 1/2 ) 4
By taking 2^( 2x - 1 ) as common fron L.H.S,
2^(2x - 1 ) ( 2 + 1 ) = 3^( x - 1/2 ) * 2^2
2^( 2x - 1 ) * 3 = 3^( x - 1/2 ) *2^2
As bases are equal , so exponent must be equal,
2x - 1 = 2 or 1 = x - 1/2
2x = 2 + 1 or 1 + 1/2 = x
2 + 1
2x = 3 or --------------- = x
2
x = 3/2
or x = 3/2.
So, x = 3/2.
By taking 3^ ( x - 1/2 ) as common from R.H.S,
(2^2)^x + 2^( 2 x - 1 ) = 3^( x - 1/2 ) ( 3 + 1 )
2^(2x ) + 2^( 2x- 1 ) = 3^( x - 1/2 ) 4
By taking 2^( 2x - 1 ) as common fron L.H.S,
2^(2x - 1 ) ( 2 + 1 ) = 3^( x - 1/2 ) * 2^2
2^( 2x - 1 ) * 3 = 3^( x - 1/2 ) *2^2
As bases are equal , so exponent must be equal,
2x - 1 = 2 or 1 = x - 1/2
2x = 2 + 1 or 1 + 1/2 = x
2 + 1
2x = 3 or --------------- = x
2
x = 3/2
or x = 3/2.
So, x = 3/2.
Lokeshwarreddy:
How have u taken common from both RHS and LHS
I have taken common seperately not in one steo only.
how explain plzz
In which step
from rhs u taken that. 3 power. from that I can't understand
From R.H.S 3^( x - 1/2 ) was taken as common because it is factor of both.
అదే ఎలా common తీశావు
What is this ?
how you have taken common ? u which state ?
Answered by
1
Answer:
Step-by-step explanation:
4^x + 2^(2x - 1 ) = 3^( x + 1/2 ) + 3^(x - 1/2)
By taking 3^ ( x - 1/2 ) as common from R.H.S,
(2^2)^x + 2^( 2 x - 1 ) = 3^( x - 1/2 ) ( 3 + 1 )
2^(2x ) + 2^( 2x- 1 ) = 3^( x - 1/2 ) 4
By taking 2^( 2x - 1 ) as common fron L.H.S,
2^(2x - 1 ) ( 2 + 1 ) = 3^( x - 1/2 ) * 2^2
2^( 2x - 1 ) * 3 = 3^( x - 1/2 ) *2^2
As bases are equal , so exponent must be equal,
2x - 1 = 2 or 1 = x - 1/2
2x = 2 + 1 or 1 + 1/2 = x
2 + 1
2x = 3 or --------------- = x
2
x = 3/2
or x = 3/2.
So, x = 3/2.
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