PLEASE SOLVE THIS .I WILL MARK AS BRAINLIEST AND I WILL THANKS TO THAT WHO WILL GIVE THE RIGHT AND APPLICABLE ANSWER.PLZ QUICK ANSWER PLEASE .
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mark me as brainliest pls.i did a lot of work for your answer.
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1st
Let the angle be x.
Its supplement is 180−x
Its complement is 90−x
So, 180−x=4×(90−x)
Or 180−x=360−4x
⟹ x= 18/3=60°
2nd I) speed = 72km/hr=20m/sec
time = 140/20=7sec
ii) Train speed = 72 km/hour
1 Km/hr = 1000/ 3600= 10/36 =5/18 metre/ second
Train speed= 72 × (5/18) m/sec
Train speed = 20 m/sec
Total distance to be covered = train length + bridge length
= 140 m + 220 m
= 360 meters
Time taken = Distance covered / Speed
Time taken by train = 360 m / 20 m/sec
Time takenby train = 18 sec
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