Question

please solve this


i will mark ur ans as brainliest​

Answer 1

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$\small\star\underline\bold\red{Given-}$

• AB = AC
• AE is drawn parallel to BC

$\small\star\underline\bold\red{To\:prove-}$

AD bisects ∠DAC.

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$\small\star\underline\bold\red{Proof-}$

In ∆ABC,

∠1 = ∠2 ...(i) ; [ angles opposite to equal sides of triangle. ]

And, AE || BC . So,

∠1 = ∠3 ....(ii) ; [ corresponding angles. ]

∠2 = ∠4 ....(iii) ; [ alternate angles. ]

From (i) , (ii) and (iii)

∠3 = ∠4

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And hence,

AE is the bisector of ∠DAC proved.

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