Question

please solve this I will mark you as brainliest and also the God of pubg​

Answer 1

Answer:

there is ans (12) 13 #88

Answer 2

Answer:

$x = 2;y = \frac{-2}{3}$

Step-by-step explanation:

Given that, $\sqrt[3]{a^{6}b^{-4}} = (a^{6}b^{-4})^{\frac{1}{3} }$

                                $= a^{2}b^{\frac{-4}{3} }$

                                $= a^{2}b^{2(\frac{-2}{3} )}$ $= a^{x}b^{2y}$

By comparing, we get    $x = 2;y = \frac{-2}{3}$