Question

please solve this

if d is the hcf of 45,27 find x,y. satisfying d=27x+45y​

Answer 1

$\huge\bf{\pink{\mid{\overline{\underline{your\:answer}}}\mid}}$

The numbers are :-

45 and 27

Lets find their HCF

BY Euclid's division Lemma :-

a = bq + r

45 = 27 x 1 + 18

27 = 18 x 1 + 9

18 = 9 x 2 + 0

HCF = d = 9

Given:-

d = 27x+45y

9 = 27x + 45y

9 = 27 - 18 x 1

18 = 45 - 27 x 1

Therefore ,

9 = 27 - [ 45 x 27 x 1 ] x 1

= 27 x 2 - 45

9 = 27 x 2 + 45 x [ -1 ]

x = 2

y = -1

☺☺☺Special Tnxx for Brainlist and following me ..

(=_=)

Answer 2

Answer:

x = 2 & y = -1

Step-by-step explanation:

hope it's helpful