Question

please solve this.....
if don't know plzzzzzzzzzzzzzzzzzzzz don't answer​

Answer 1

Answer:

Use of trignometric Identities will help you

Explanation:

1.SinA= opposite side/adjacent side

this can also be written as: 1/CosecA

By $1+Cot^2A= Cosec^2A$

so,

SinA= $1/$$\sqrt{1+cot^2A$  - - - - - - (1)

2. SecA= $\sqrt1+Tan^2A$

so, SecA= $\sqrt Cot^2A+1/Cot^2A$ - - - - (2)

* since TanA= 1/cotA*

3. TanA= 1/CotA