Question

Please solve this
If
$x {}^{2} + \frac{1}{x {}^{2} } = 6$find the value of
$x {}^{4} + \frac{1}{x {}^{4} }$
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Answer 1

Answer:

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Step-by-step explanation:

$To \: find : - \\ x {}^{4} + \frac{1}{x {}^{4} } \\ \\ so \: here \: \\ x {}^{2} + \frac{1}{x {}^{2} } = 6 \\ \\ squaring \: both \: sides \\ we \: get \\ = x {}^{4} + \frac{1}{x {}^{4} } \: + \: 2.x {}^{2} . \frac{1}{x {}^{2} } = 36 \\ \\ = x {}^{4} + \frac{1}{x {}^{4} } \: + \: 2 = 36 \\ \\ ie \: \: x {}^{4} + \frac{1}{x {}^{4} } = 34$