Question

please solve this
If you don't know not need to give answer ​

Answer 1

Given x+y=8

xy=10

Since x³+y³=(x+y)(x²-xy+y²)........eqn1

Hence first we need to find x²+y²,

So (x+y)²= x²+y²+2xy

Or, 8²= x²+y²+20

Or,x²+y²=64-20=44

By putting the values of (x+y), xy,and x²+y²,in eqn1

X³+y³=(8)(44+10)

        =432 answer

Answer 2

Answer:

if x+y= 8 and xy=10  then find  x^3 + y^3 = ?

Note: "^" denoted power

as we know that:

   (x+y)^3= x^3 + 3yx^2 + 3xy^2 + y^3

we can also write it as:

  (x+y)^3= x^3 + y^3+ 3xy(x + y)

  x^3 + y^3 = - (x+y)^3 + 3xy(x + y)

Now put the values:

   x^3 + y^3 = -(8)^3 + 3(10)(8)

   x^3 + y^3 = -512 + 240

   x^3 + y^3 = -272   Ans

Step-by-step explanation: