Question

please solve this .

if you don't know not need to give any comments. ​

Answer 1

Answer:

Explanation:

Given;

u=0

d=5km=5000m

t=30min=1800s

Average speed = total distance / total time

s=5000/1800

s=2.77m/s

Average velocity=total displacement/total time

v=0/1800(: displacement  is zero if the initial position and final position is same)

v=0

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Answer 2

Given:

Distance covered during ride,d= 5 km

Time taken,t= 30 min

To Find:

Average velocity and average speed

Solution:

We know that,

• Average velocity V is given by

$\underline{\pink{\boxed{\bf{V=\dfrac{Total\ Displacement}{Total\ Time\ taken}}}}}$

• Average speed S is given by

$\underline{\purple{\boxed{\bf{S=\dfrac{Total\ Distance\ covered}{Total\ Time\ taken}}}}}$

$\rule{190}{1}$

It is given that,

$\longrightarrow\rm{t=30\ min=\dfrac{30}{60}\ h=0.5\ h}$'

$\rule{190}{1}$

Since, I returned to the same gate from where I have started

So, my displacement D will be

$\longrightarrow\rm{D=0\ km}$

Now, let the average velocity and average speed of mine be V and S respectively

So,

$\longrightarrow\rm{V=\dfrac{Total\ Displacement}{Total\ Time\ taken}}$

$\longrightarrow\rm{V=\dfrac{D}{t}}$

$\longrightarrow\rm{V=\dfrac{0}{0.5}}$

$\longrightarrow\rm\green{V=0\ km/h}$

Also,

$\longrightarrow\rm{S=\dfrac{Total\ Distance\ covered}{Total\ Time\ taken}}$

$\longrightarrow\rm{S=\dfrac{d}{t}}$

$\longrightarrow\rm{S=\dfrac{5}{0.5}}$

$\longrightarrow\rm\green{S=10\ km/h}$

Hence, average velocity is 0 km/h and average speed is 10 km/h.