Math, asked by mamtachatterjee437, 8 months ago

please solve this if you know the answer​

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Answered by adiyar2007nmhss
1

Answer:

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Step-by-step explanation:

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Answered by sakshi2005sharma30
0

Answer:

LHS. (sinA - sinB)(sinA + sinB) + (cosA - cosB)(cosA + cosB) / (cosA + cosB)(sinA + sinB)

(sin²A - sin²B + cos²A - cos²B) / (cosA + cosB)(sinA + sinB)

sin²A + cos²A - (sin²B + cos²B) / (cosA + cosB)(sinA + sinB)

1 - 1 / (cosA + cosB)(sinA + sinB)

0 / (cosA + cosB)(sinA + sinB)

0

LHS = RHS

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