Question

please solve this..ill.mark u as brainliest...plzz​

Answer 1

Step-by-step explanation:

think your question is :

1

+

cos

x

−

sin

2

x

sin

x

(

1

+

cos

x

)

=

cot

x

L

H

S

=

1

+

cos

x

−

sin

2

x

sin

x

(

1

+

cos

x

)

→

[

∵

cos

2

θ

+

sin

2

θ

=

1

]

L

H

S

=

(

1

+

cos

x

)

−

(

1

−

cos

2

x

)

sin

x

(

1

+

cos

x

)

L

H

S

=

(

1

+

cos

x

)

−

(

1

−

cos

x

)

(

1

+

cos

x

)

sin

x

(

1

+

cos

x

)

L

H

S

=

(

1

+

cos

x

)

[

1

−

(

1

−

cos

x

)

]

sin

x

(

1

+

cos

x

)

L

H

S

=

1

−

1

+

cos

x

sin

x

L

H

S

=

cos

x

sin

x

LHS=cotx

LHS=RHS.

Answer 2

Step-by-step explanation:

Solve the numerator on L. H. S

(*sin^2=1-cos^2)

Thus,numerator will be

1+cos-(1-cos^2)

Solve numerator

Take common and cancel it out

Now, L. H. S=cos/sin

Cot =cos/sin

L. H. S=cot

L. H. S=R. H. S

HENCE PROVED