Question

PLEASE SOLVE THIS!!! In ΔABC, AC= 8 cm and BC= 5cm. If the area of ΔABC is 10√2 cm², find the value of ∠ACB

Answer 1

Step-by-step explanation:

Area of paralleogram ABCD = DC × AE (Taking base as DC and Height as AE )

Area of paralleogram ABCD = AB × AE (AB = DC as opposite side of the parallelogram are equal)

Therefore,

Area of paralleogram ABCD = 16 × 8 ……(1)

Taking the base of Parallelogram ABCD as AD we get

Area of paralleogram ABCD = AD × CF (taking base as AD and height as CF)

Area of paralleogram ABCD = AD × 10 ……(2)

Since equation 1 and 2 both represent the Area of the same Parallelogram ABCD , both should be equal.

Hence fro equation (1) and (2),

This means that,

16 x 8 = AD x 10

AD= 16 x 8 /10

AD = 12.8 cm

Hence we get the result as AD= 12.8