Question

Please Solve this Inequality 1/x-2≤2, 1/x-2 is equal to or less than 2

Answer 1

Step-by-step explanation:

$\frac{1}{x - 2} \leqslant 2$

$= > \frac{1}{x - 2} - 2 \leqslant 0$

$= > \frac{1 - 2(x - 2)}{x - 2} \leqslant 0$

$= > \frac{1 - 2x + 4}{x - 2} \leqslant 0$

Multiplying both side by '-', so sign of inequality will be changed,

$= > \frac{2x - 5}{x - 2} \geqslant 0$

$= > x \in( - \infty \: to \: 2) \: union \: ( \frac{5}{2} \: to \: \ \infty )$

Answer 2

Answer:

x<−52× or ×−1<x<2. Explanation: First of all, note that your inequality is only defined if your denominators are not equal to zero:.

Step-by-step explanation:

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