Math, asked by rk3284499, 1 year ago

please solve this integration​

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Answered by Anonymous
7

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Answered by Anonymous
401

\LARGE\underline{\bf{\red{Answer}}}

\displaystyle\sf\int\dfrac{dx}{5-8x-x^2}

\displaystyle\sf=\int\dfrac{dx}{5-(8x+x^2)}

\displaystyle\sf = \int\dfrac{dx}{5-(x^2+8x+16-16)}

\displaystyle\sf = \int\dfrac{dx}{21-(x+4)^2}

\displaystyle\sf = \int\dfrac{dx}{\sqrt{21} -(x+4)^2}

\displaystyle\sf = \dfrac{1}{2\sqrt{22}} \: log \left|\dfrac{\sqrt{21}+(x+4)}{\sqrt{21}-(x+4)}\right| + C

\displaystyle\boxed{\sf = \dfrac{1}{2\sqrt{22}} \: log \left|\dfrac{\sqrt{21}+x+4}{\sqrt{21}-x+4}\right| + C}

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