Question

please solve this intergration question​

Answer 1

Step-by-step explanation:

We have,

$\int^{3}_{0} ( {x}^{2} + 2x + 1)dx$

$= \int^{3}_{0} ( x + 1)^{2} dx$

$= \bigg [ \frac{ ( x + 1)^{3}}{3} \bigg]^{3}_{0}$

$= \frac{ ( 3 + 1)^{3}}{3} - \frac{(0 + 1)^{3} }{3}$

$= \frac{ ( 4)^{3}}{3} - \frac{(0 + 1)^{3} }{3}$

$= \frac{ 64}{3} - \frac{ 1}{3}$

$= \frac{ 63}{3}$

$= 21$

Answer 2

Answer:

hope that helps ✌!!!!!!!!!