Math, asked by Souvik93, 10 months ago

please solve this intrigration

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Answered by sprao534
2
Please see the attachment
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soubhik: hello,buddy
Answered by Anonymous
114

Question :

Integrate :

1) sin inverse root x /a+x

2) x^2 dx/(x^2+a^2)(x^2+b^2)

Solution :

1)   \sf\int \sin {}^{ - 1}  \sqrt{ \dfrac{x}{a + x} }  \times dx

Let   \sf \: x = a \tan { }^{2}  \theta

 \sf \implies \frac{dx}{d \theta}  = 2a \times  \tan \theta \times  \sec {}^{2}  \theta

 \sf \implies \: dx = 2a \tan \theta \sec {}^{2}  \theta  \: d \theta

put this value in integration

 \sf \int sin {}^{ - 1}  \sqrt{ \dfrac{x}{a + x} } dx

 \sf =  \int \sin {}^{ - 1}  \sqrt{ \dfrac{a \tan {}^{2} \theta }{a + a \tan {}^{2}  \theta} }  \times 2a \tan \theta \sec {}^{2}  \theta d \theta

 \sf =  \int  \sin {}^{ - 1}  \sqrt{ \dfrac{ \cancel{a} \tan {}^{2}  \theta}{ \cancel{a}(1  +  \tan {}^{2}  \theta)} }  \times 2a \tan \theta \sec {}^{2}  \theta d \theta

 \sf =   \int \sin {}^{ - 1}  \sqrt{ \dfrac{ \tan \theta}{ \sec \theta} }  \times 2a \tan \theta \sec {}^{2}  \theta d \theta

 \sf =  \int \sin {}^{ - 1} ( \sin \theta)  \times 2a \tan \theta \sec {}^{2}  \theta d \theta

 \sf = 2a \int \theta \tan \theta \sec {}^{2}  \theta d\theta

Now integrate ,by using Integration by parts

Let θ= First function and other one as second function

  \sf = 2a( \theta \int \tan \theta \sec {}^{2}  \theta d\theta -  \int 1\times  \tan \theta  \sec {}^{2}  \theta \:d \theta)

 \sf = 2a( \theta \times  \dfrac{ \tan {}^{2}  \theta}{2}  - \int \sec {}^{2} \theta \tan \theta d \theta)

 \sf = 2a( \theta \times  \dfrac{ \tan {}^{2}  \theta}{2}  -  \int \dfrac{\tan{}^{2}\theta}{2})

 \sf = a( \theta \times  \tan {}^{2}  \theta -  \int( \sec {}^{2}  \theta - 1)d \theta) + c

 \sf = a ( \theta \tan {}^{2}   \theta -  \tan \theta +  \theta) + c

 \sf = a( \dfrac{x}{a}  \tan {}^{ - 1} \sqrt{ \dfrac{x}{a} }   -  \sqrt{ \dfrac{x}{a} }  +  \tan {}^{ - 1}  \sqrt{ \dfrac{x}{a} } ) + c

2)

 \sf \int \dfrac{x {}^{2} }{(x {}^{2} + a {}^{2} )(b {}^{2}  + x {}^{2}  )} dx

 \sf =  \dfrac{1}{b {}^{2}  - a {}^{2} } (b \tan {}^{ - 1} ( \dfrac{x}{b} ) - a \tan {}^{ - 1} ( \dfrac{x}{a} )) + c

for step by step Explanation refer to the attachment.

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