Question

please solve this irrelevant questions will delete ​

Answer 1

Step-by-step explanation:

AB is a chord of a circle with centre O AB is produced to C such that BO = BC

CO is joined and produced to meet the circle at D

We shall prove x∘

=3y∘

We have

BC=OB

∠OCB=∠BOC=y∘

[Angles opposite to equal sides are equal ]

∠OBA=∠BOC+∠OCB

[Ext angle of a △ is equal to the sum of the opposite interior angles ]

⇒∠OBC=y∘ +y∘ =2y∘

OA=OB...[Radii of the same circle ]

∠OAB=∠OBA....[Angles opp. To equal sides of a △]

=2y∘

∠AOD=∠OAC+∠OCA

=2y⁰ +y∘

=3y∘ [Exterior angle - Sum of opposite interrior angles]

⇒x∘ =3y∘

Answer 2

Answer:

A line segment connecting two points on a curve. Example: the line segment connecting two points on a circle's circumference is a chord. When the chord passes through the center of a circle it is called the diameter