Question

please solve this is very imprortant and urgent​

Answer 1

Answer:

1) E = {14,17}

2) E = {1,8,27,64}

3) D = {1,3,9,27,81}

4) E = {-15,15}

Step-by-step explanation:

1) Given: E = {x : x=3a+5, 2<a<5 , a∈N}

∵a∈N and a lies between 2 and 5(both excluded). ∴a=3 or a=4.

⇒For a=3, x = 3×3+5 = 9+5 = 14 and for a=4, x = 3×4+5 = 12+5 = 17

⇒ E = {14,17}

2) Given: E = {x : x=a³, a<5 , a∈N}

∵a∈N and a is less than 5. ∴a=1 or a=2 or a=3 or a=4.

⇒For a=1, x = 1³ = 1

For a=2, x = 2³ = 8

For a=3, x = 3³ = 27

For a=4, x = 4³ = 64

⇒ E = {1,8,27,64}

3) Given: D = {x : x=$\frac{81}{a}$, a∈N , x∈N}

∵Both a and x are natural numbers. ∴a must be a natural number such that it is a divisor of 81.

⇒a=1 or a=3 or a=9 or a=27 or a=81.

⇒For a=1, x = 81÷1 = 81

For a=3, x = 81÷3 = 27

For a=9, x = 81÷9 = 9

For a=27, x = 81÷27 = 3

For a=81, x = 81÷81 = 1

⇒ D = {1,3,9,27,81}

4) Given: E = {x : x=√625, x∈Z}

∵√625 is a perfect square. ∴x = ±25.

Also, x is an integer(either positive or negative). ∴Both values of x(i.e., +15 and -15) will be accepted.

⇒ E = {-15,15}

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